A dihybrid testcross is made to determine if genes C and D are linked.The results are shown in the table.
$\begin{array}{|l|c|r|}\hline \text { Parent genotypes: } & C c  D d \times c c d d & \\\hline & C c  D d & 222 \\\hline & C c  d d & 280 \\\hline \text { Progeny genotypes: } & c c  D d & 280 \\\hline & c c  d d & 218 \\\hline & & 1000 \\\hline\end{array}$ $\begin{array}{|l|c|r|} \hline \text { Parent genotypes: } & C c  D d \times c c d d & \\ \hline & C c  D d & 222 \\ \hline & C c  d d & 280 \\ \hline \text { Progeny genotypes: } & c c  D d & 280 \\ \hline & c c  d d & 218 \\ \hline & & 1000 \\ \hline \end{array}$ -Using the chi-square test for goodness of fit, how many degrees of freedom are in this data set? A)1 B)2 C)3 D)4" class="answers-bank-image d-block" loading="lazy" >
-Using the chi-square test for goodness of fit, how many degrees of freedom are in this data set?

In peas, tall (T)is dominant to short (t), red flowers (R)is dominant to white flowers (r), and wide leaves (W)is dominant to narrow leaves (w).A tall plant that has red flowers and wide leaves is crossed to a short plant that has white flowers and narrow leaves.The resulting progeny are shown in the table.
$\begin{array}{|l|r|}\hline \text { tall, red, wide } & 381 \\\hline \text { tall, white, wide } & 122 \\\hline \text { short, red, wide } & 118 \\\hline \text { short, white, wide } & 379 \\\hline & 1000 \\\hline\end{array}$
-What is the genotype of the tall plant that has red flowers and wide leaves?

A dihybrid testcross is made to determine if genes C and D are linked.The results are shown in the table.
$\begin{array}{|l|c|r|}\hline \text { Parent genotypes: } & C c  D d \times c c d d & \\\hline & C c  D d & 222 \\\hline & C c  d d & 280 \\\hline \text { Progeny genotypes: } & c c  D d & 280 \\\hline & c c  d d & 218 \\\hline & & 1000 \\\hline\end{array}$ $\begin{array}{|l|c|r|} \hline \text { Parent genotypes: } & C c  D d \times c c d d & \\ \hline & C c  D d & 222 \\ \hline & C c  d d & 280 \\ \hline \text { Progeny genotypes: } & c c  D d & 280 \\ \hline & c c  d d & 218 \\ \hline & & 1000 \\ \hline \end{array}$ -The chi-square value is the sum for all progeny classes of (observed-expected)²/expected.Using the chi-square test for goodness of fit, calculate the chi-square value to test the null hypothesis that genes C and D are unlinked.What is the chi-square value? A)0 B)0.0576 C)10.8 D)14.4 E)cannot be determined" class="answers-bank-image d-block" loading="lazy" >
-The chi-square value is the sum for all progeny classes of (observed-expected)²/expected.Using the chi-square test for goodness of fit, calculate the chi-square value to test the null hypothesis that genes C and D are unlinked.What is the chi-square value?