In glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free-energy change ( $\Delta$ G'°) of 23.8 kJ/mol. Under what conditions encountered in a normal cell will the free-energy change ( $\Delta$ G) be negative, enabling the reaction to proceed spontaneously to the right?

A) Under standard conditions, enough energy is released to drive the reaction to the right.
B) The reaction will not go to the right spontaneously under any conditions because the $\Delta$ G'° is positive.
C) The reaction will proceed spontaneously to the right if there is a high concentration of products relative to the concentration of fructose 1,6-bisphosphate.
D) The reaction will proceed spontaneously to the right if there is a high concentration of fructose 1,6-bisphosphate relative to the concentration of products.
E) None of these conditions is sufficient.