Question 16

(Multiple Choice)

In Drosophila, the genes y, f, and v are all X-linked. Females who are homozygous for recessive alleles of all three genes (y f v / y f v) are crossed to wild-type males. The resulting trihybrid F1 females are testcrossed. The F2 are distributed as follows:

yfv3210yfv+72yf+v1024yf+v+678y+fv690y+fv+1044y+f+v60y+f+v+322210,000\begin{array} { | l | r | } \hline y f v & 3210 \\\hline y f v ^ { + } & 72 \\\hline y f ^ { + } v & 1024 \\\hline y f ^ { + } v^ + & 678 \\\hline y ^ { + } f v & 690 \\\hline y ^ { + } f v ^+ & 1044 \\\hline y ^ { + } f ^+ v & 60 \\\hline y ^ { + } f ^+ v^ + & 3222 \\\hline & 10,000 \\\hline\end{array}

-Which of the following linkage maps correctly shows the order and distance between the y, f, and v genes?


A)f--35 m.u.--y--15 m.u.--v
B)f--22 m.u.--y--15 m.u.--v
C)y--35 m.u.--f--22 m.u.--v
D)y--22 m.u.--v--15 m.u.--f
E)y--15 m.u.--v--22 m.u.--f

Answer