A short segment of an mRNA molecule is shown below. The polypeptide it codes for is also shown: 5′-AUGGUGCUGAAG-3′: methionine-valine-leucine-lysine
Assume that a mutation in the DNA occurs so that the fourth base (counting from the 5′ end) of the messenger RNA now reads A rather than G. What sequence of amino acids will the mRNA now code for? (You do not need a copy of the genetic code to answer the question.)