-What will happen to a red blood cell (RBC),which has an internal ion concentration of about 0.9 percent,if it is placed into a beaker of pure water?

A)The cell would shrink because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
B)The cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the RBC.
C)The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
D)The cell will remain the same size because the solution outside the cell is isotonic.
E)The cell will remain the same size because the solution outside the cell is hypotonic.