For the reaction 2HgO(s) → 2Hg(l) + O2(g), we measure the evolution of gas to determine the rate of reaction. At the beginning of the reaction (at 0 min), 0.070 L of O2 is present. After 15 min, the volume of O2 is 0.40 L. What is the rate of reaction?
A) 0.022 L/min B) 0.033 L/min C) 0.23 L/min D) 0.33 L/min