In a reversible chemical reaction at equilibrium,the concentration of X (the reactant)is 0.75 mol/L,and the concentration of Y (the product)is 2.25 mol/L.At 25°C,what would be the K_eq?

Question

In a reversible chemical reaction at equilibrium,the concentration of X (the reactant)is 0.75 mol/L,and the concentration of Y (the product)is 2.25 mol/L.At 25°C,what would be the Keq?

In a reversible chemical reaction at equilibrium,the concentration of X (the reactant)is 0.75 mol/L,and the concentration of Y (the product)is 2.25 mol/L.At 25°C,what would be the K_eq?